3x^2+25x=-14

Solution for 3x^2+25x=-14 equation:

3x^2+25x=-14

We move all terms to the left:

3x^2+25x-(-14)=0

We add all the numbers together, and all the variables

3x^2+25x+14=0

a = 3; b = 25; c = +14;
Δ = b2-4ac
Δ = 252-4·3·14
Δ = 457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{457}}{2*3}=\frac{-25-\sqrt{457}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{457}}{2*3}=\frac{-25+\sqrt{457}}{6}
$